2k^2-104k+672=0

Solution for 2k^2-104k+672=0 equation:

2k^2-104k+672=0

a = 2; b = -104; c = +672;
Δ = b2-4ac
Δ = -1042-4·2·672
Δ = 5440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5440}=\sqrt{64*85}=\sqrt{64}*\sqrt{85}=8\sqrt{85}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-8\sqrt{85}}{2*2}=\frac{104-8\sqrt{85}}{4}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+8\sqrt{85}}{2*2}=\frac{104+8\sqrt{85}}{4}
$